This will blow people's mental models of C (genuine example):
#include <stdio.h>
int main()
{
char const* c = "hello";
// this is the interesting bit - n[c] == c[n] (n = number literal) !!! I swear, try it.
printf("This program compiles and prints:'%c %c %c %c %c'\n",
0[c], 1[c], 2[c], 3[c], 4[c]);
return 0;
}
// See? I read that both forms are translated to *(c + n),
// which explains the equivalence. Weird, no?
See? I read that both forms are translated to * (c + n), which
explains the equivalence. Weird, no?
Well, that surely is evil, yet perfectly valid C code. But personally, I don't find it surprising. Of course, you need to grok what A[n] really is -- i.e., syntactic sugar for *(A + n), as you just explained.
