You could use Function.prototype.bind in a couple ways, or even Array.prototype.map (though sadly you can't really do new Array(n).map, if that was true you could make this a one-liner).
// new Array(n) could just be [] in all examples
//
// using Array.prototype.map
// sadly you can't do new Array(n).map
// because it doesn't iterate over undefined functions
function foo(n) {
for (var ret = new Array(n), i = 0; i < n; ++i) {
ret[i] = i;
}
return ret.map(function(_,n) { return function() { return n; }; });
}
// using Function.prototype.bind in a couple ways
function foo(n) {
function num() { return +this; }
for (var ret = new Array(n), i = 0; i < n; ++i) {
ret[i] = num.bind(i);
}
return ret;
}
function foo(n) {
function num(a) { return a; }
for (var ret = new Array(n), i = 0; i < n; ++i) {
ret[i] = num.bind(null, i); // could bind this to pretty much whatever here
}
return ret;
}
Close, but I checked it and the value of `i` won't bind to the function. You also have to use `...` (exclusive range) instead of `..` to prevent an off-by-one error.
Here's one way:
foo = (n) -> ((a) -> a).bind(null, i) for i in [0...n]
