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This is one of my favourite problems, I still remember that it has a very real edge case even though I solved it more than 10 years ago. Thank you for the problem!


I'm guessing if you only calculate based on the digits, the probability is going to be slightly different than the real one, because you only have a finite number of plates you can choose from.


I'm glad you enjoyed! It was a real game I played when driving around.


Is your real name also Seth? This is wholesome and hilarious


Yes, the other name in the problem is my sister's name :)


Sounds like the birthday paradox problem. Is it?


Nearly, but not 8 digits of precision worth.


Can you reuse a plate with 500?


The wording seems to strongly imply no; you need two separate plates with 500 on them.




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