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I admit to not having that much experience in prolog, but I'm having a hard time translating the time parameter `[n]` into executable prolog. Anyone got a clue?


that is prolog pseudocode. You would probably use the lists:nth/3 predicate.

https://www.scryer.pl/lists

Markus Triska has probably the best resources on modern Prolog.

Just search for "Power of Prolog" on YouTube or the internets.




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